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因式分解法教案,
(4)(x-7)(x-5)=0 x1=7,x2=5
2.x+y=0或x+y-1=0,即x+y=0或x+y=1
3.设宽为x,则长为35-2x,依题意,得x(35-2x)=150
2x2-35x+150=0
(2x-15)(x-10)=0,
x1=7.5,x2=10,
当宽x1=7.5时,长为35-2x=20,
当宽x=10时,长为15,
因a≥20m,两根都满足条件.
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，因式分解法教案
